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Re: temperature test
Hi All,
Attached is a file showing a scope shot from a FEU-84-3 pmt with
Cockcroft-Walton base. the Voltage is set to 1950V.
There are signals as the PMT is not completely shielded from the
ambient light.
Now some comments:
1) if I assume a signal height of 1V and as signal shape a triangle
with base 50ns. I get a peak current of 20mA and the signal results
in 5*10^-12C.
assuming a very high rate of 50kHz this will lead to 0.25*10^-6C.
this charge corresponds to a effective DC current 0.25uA.
Taking the 1V*0.25uA=0.25uWatt. That is what the PMT will consume
as power.
please correct me if this is all wrong.
2) as you pointed out the base consumes more power than the PMT but
since it is a Cockcroft-Walton type base it will consume about 0.1Watt
according to Paul Smith.
3) the holes in the plastic are very tight for the bases so I can not fit
a temperature probe next to the base in the plastic block, but rather
feed the temperature probe from the PMT side into the hole so that
it is located next to the pmt.
From the above estimate in 1) I will not see a temperature change as
the power dissipation must be small also since the actual signals are
much smaller than 1V. But rather I have to make the holes bigger such
that a temperature probe fits next to the base.
4) Maybe we make an elefant out of a mosquito:
assuming 0.1 Watt per pmt we talk about 300 Watt in total. While this
number is not negligible we have to see that this power is distributed
over a rather larger area of more than 2 x 2 meters. And also the volume
is not small as the base is about 15cm long and 1/3 will stick out
of the plastic
wall. The whole thing sits in a light tight hut that can be equipped
with fans
and exhausts to provide substantial air cooling. Note 300Watt is
1PC power
supply.
5) I am currently repeating the test and making sure that at the
location where
I measure the temperature I have no air exchange. however the PMT is
cooled
where it sticks out of the plastic block by the surrounding air.
and as indicated
in the attached picture the signals are only 50 to 100mV.
As usual I am looking forward to your comments and suggestions.
cheers,
Beni